Tính: \(\,A = {\left( { - 1,5} \right)^2}.2\frac{2}{3}.\frac{1}{6} + \left( {\frac{4}{7} - \frac{2}{5}} \right):1\frac{1}{{35}}\)

* Hướng dẫn giải

\(\begin{array}{l}\,A = {\left( { - 1,5} \right)^2}.2\frac{2}{3}.\frac{1}{6} + \left( {\frac{4}{7} - \frac{2}{5}} \right):1\frac{1}{{35}}\\ = {\left( { - \frac{3}{2}} \right)^2}.\frac{8}{3}.\frac{1}{6} + \left( {\frac{{20}}{{35}} - \frac{{14}}{{35}}} \right):\frac{{36}}{{35}} = \frac{9}{4}.\frac{8}{3}.\frac{1}{6} + \frac{6}{{35}}:\frac{{36}}{{35}}\\ = 1 + \frac{6}{{35}}.\frac{{35}}{{36}}\\ = 1 + \frac{1}{6}\\ = \frac{7}{6}\end{array}\)

Chọn B