Tính: \(\,7\frac{5}{{11}} - \left( {2\frac{3}{7} + 3\frac{5}{{11}}} \right)\)

* Hướng dẫn giải

\(\begin{array}{l}\,7\frac{5}{{11}} - \left( {2\frac{3}{7} + 3\frac{5}{{11}}} \right) = 7 + \frac{5}{{11}} - \left( {2 + \frac{3}{7} + 3 + \frac{5}{{11}}} \right)\\\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\, = 7 + \frac{5}{{11}} - 2 - 3 - \frac{3}{7} - \frac{5}{{11}}\\\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\, = \left( {7 - 2 - 3} \right) + \left( {\frac{5}{{11}} - \frac{5}{{11}}} \right) - \frac{3}{7}\\\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\, = 2 + 0 - \frac{3}{7}\\\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\, = \frac{{11}}{7}\end{array}\)

Chọn B