PHẦN II. TỰ LUẬN
Thực hiện phép tính (tính hợp lí nếu có thể):
a) \[25\% - 1\frac{1}{4} + 0,2:\frac{6}{5}\];
b) \[\frac{8}{9} + \frac{1}{9}.\frac{2}{9} + \frac{1}{9}.\frac{7}{9}\];
c) \(\frac{5}{{39}}\,\, \cdot \,\left( {\,7\frac{4}{5}\,\, \cdot \,1\frac{2}{3}\,\, + \,\,8\frac{1}{3}\, \cdot \,7\frac{4}{5}\,} \right)\)
Hướng dẫn giải:
a) \[25\% - 1\frac{1}{4} + 0,2:\frac{6}{5}\]
\[ = \frac{{25}}{{100}} - \frac{5}{4} + \frac{1}{5}:\frac{6}{5}\]
\[ = \frac{1}{4} - \frac{5}{4} + \frac{1}{5}.\frac{5}{6}\]
\[ = \left( {\frac{1}{4} - \frac{5}{4}} \right) + \frac{{1.5}}{{5.6}}\]
\[ = \frac{{ - 4}}{4} + \frac{1}{6}\]
\[ = - 1 + \frac{1}{6}\]
\[ = \frac{{ - 6}}{6} + \frac{1}{6}\]
\[ = \frac{{ - 5}}{6}\]
b) \[\frac{8}{9} + \frac{1}{9}.\frac{2}{9} + \frac{1}{9}.\frac{7}{9}\]
\[ = \frac{8}{9} + \left( {\frac{1}{9}.\frac{2}{9} + \frac{1}{9}.\frac{7}{9}} \right)\]
\[ = \frac{8}{9} + \frac{1}{9}.\left( {\frac{2}{9} + \frac{7}{9}} \right)\]
\[ = \frac{8}{9} + \frac{1}{9}.\frac{9}{9}\]
\[ = \frac{8}{9} + \frac{1}{9}.1\]
\( = \frac{8}{9} + \frac{1}{9}\)
\( = \frac{9}{9}\)
= 1.
c) \(\frac{5}{{39}}{\mkern 1mu} {\mkern 1mu} \, \cdot {\mkern 1mu} \,\left( {{\mkern 1mu} 7\frac{4}{5}\,{\mkern 1mu} {\mkern 1mu} \cdot \,1\frac{2}{3}{\mkern 1mu} {\mkern 1mu} \, + {\mkern 1mu} {\mkern 1mu} \,8\frac{1}{3}\,\, \cdot \,\,7\frac{4}{5}{\mkern 1mu} } \right)\)
\( = \,{\mkern 1mu} \frac{5}{{39}}{\mkern 1mu} {\mkern 1mu} \cdot \,{\mkern 1mu} \left[ {{\mkern 1mu} 7{\mkern 1mu} \frac{4}{5}\,{\mkern 1mu} \cdot \,{\mkern 1mu} \left( {1\frac{2}{3} + {\mkern 1mu} {\mkern 1mu} 8\frac{1}{3}{\mkern 1mu} } \right)} \right]\)
\( = \,{\mkern 1mu} \frac{5}{{39}}{\mkern 1mu} \, \cdot \,\frac{{39}}{5}{\mkern 1mu} \,\left( {1 + \frac{2}{3} + 8 + \frac{1}{3}} \right){\mkern 1mu} \)
\( = \,{\mkern 1mu} {\mkern 1mu} \frac{{5.39}}{{39.5}}{\mkern 1mu} {\mkern 1mu} \cdot\,{\mkern 1mu} \,\left( {9 + \frac{2}{3} + \frac{1}{3}} \right){\mkern 1mu} \)
\( = \,1{\mkern 1mu} \cdot\,\left( {9\, + \frac{3}{3}} \right){\mkern 1mu} \)
= 9 + 1
= 10.
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