A.\[y' = \frac{{\sin \frac{x}{2}}}{{2{{\cos }^3}\frac{x}{2}}}\]
B. \[y' = {\tan ^3}\frac{x}{2}\]
C. \[y' = \frac{{\sin \frac{x}{2}}}{{co{s^3}\frac{x}{2}}}\]
D. \[y' = \frac{{2\sin \frac{x}{2}}}{{{{\cos }^3}\frac{x}{2}}}\]
Bước 1:
\[\begin{array}{*{20}{l}}{{{\left( {{{\tan }^2}\frac{x}{2}} \right)}^\prime } = 2\tan \frac{x}{2}{{\left( {\tan \frac{x}{2}} \right)}^\prime }}\end{array}\]
Bước 2:
\[ = 2\tan \frac{x}{2}.\frac{{{{\left( {\frac{x}{2}} \right)}^\prime }}}{{{{\cos }^2}\frac{x}{2}}}\]
\[ = 2\tan \frac{x}{2}.\frac{{\frac{1}{2}}}{{{{\cos }^2}\frac{x}{2}}} = \frac{{\sin \frac{x}{2}}}{{\cos \frac{x}{2}}}.\frac{1}{{{{\cos }^2}\frac{x}{2}}} = \frac{{\sin \frac{x}{2}}}{{{{\cos }^3}\frac{x}{2}}}\]
Đáp án cần chọn là: C
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