Đạo hàm hàm số y = log 2018 ( 2018 x + 1 ) là:

Ta có:

\[{\left[ {{{\log }_{2018}}\left( {2018x + 1} \right)} \right]^\prime } = \frac{{{{\left( {2018x + 1} \right)}^\prime }}}{{\left( {2018x + 1} \right)\ln 2018}} = \frac{{2018}}{{\left( {2018x + 1} \right)\ln 2018}}\]