Cho tứ diện ABCD có trọng tâm G. Chọn khẳng định đúng?

A. $A{B}^2+A{C}^2+A{D}^2+B{C}^2+B{D}^2+C{D}^2=3\left(G{A}^2+G{B}^2+G{C}^2+G{D}^2\right)$

B. $A{B}^2+A{C}^2+A{D}^2+B{C}^2+B{D}^2+C{D}^2=4\left(G{A}^2+G{B}^2+G{C}^2+G{D}^2\right)$

C. $A{B}^2+A{C}^2+A{D}^2+B{C}^2+B{D}^2+C{D}^2=6\left(G{A}^2+G{B}^2+G{C}^2+G{D}^2\right)$

D. $A{B}^2+A{C}^2+A{D}^2+B{C}^2+B{D}^2+C{D}^2=2\left(G{A}^2+G{B}^2+G{C}^2+G{D}^2\right)$