A. -1
B. 2
C. 1
D. 0
C
\(C = \dfrac{{ - 2018}}{{2019}}.\dfrac{2}{7} - \dfrac{{2018}}{{2019}}.\dfrac{5}{7} + 1\dfrac{{2018}}{{2019}}\)
\( = \dfrac{{ - 2018}}{{2019}}.\dfrac{2}{7} + \dfrac{{ - 2018}}{{2019}}.\dfrac{5}{7}\)\( + \left( {1 + \dfrac{{2018}}{{2019}}} \right)\)
\(\begin{array}{l} = \dfrac{{ - 2018}}{{2019}}.\left( {\dfrac{2}{7} + \dfrac{5}{7}} \right) + 1 + \dfrac{{2018}}{{2019}}\\ = \dfrac{{ - 2018}}{{2019}}.\dfrac{7}{7} + 1 + \dfrac{{2018}}{{2019}}\\ = \dfrac{{ - 2018}}{{2019}} + 1 + \dfrac{{2018}}{{2019}}\\ = \dfrac{{ - 2018}}{{2019}} + \dfrac{{2018}}{{2019}} + 1\\ = 0 + 1 = 1\end{array}\)
Câu hỏi trên thuộc đề trắc nghiệm dưới đây !
Copyright © 2021 HOCTAP247