Tìm số nguyên x, biết 3 / 2x+1 + 10 / 4z+2 - 6 / 6x+3 = 12/26

* Hướng dẫn giải

$\begin{array}{l}\frac{3}{2x+1}+\frac{10}{4x+2}-\frac{6}{6x+3}=\frac{12}{26}\\ \Rightarrow \frac{3}{2x+1}+\frac{10}{2\left(2x+1\right)}-\frac{6}{3\left(2x+1\right)}=\frac{12}{26}\\ \Rightarrow \frac{3}{2x+1}+\frac{5}{2x+1}-\frac{2}{2x+1}=\frac{12}{26}\\ \Rightarrow \frac{3+5-2}{2x+1}=\frac{12}{26}\\ \Rightarrow \frac{6}{2x+1}=\frac{6}{13}\\ \Rightarrow 2x+1=13\\ \Rightarrow x=6\end{array}$