Đáp án:

Bạn tham khảo~

Tóm tắt:

`V_{\text{dd HCl}} = 210 (ml)`

`D_{HCl} = 1,19` $g/mol$

$\underline{\text{C%}_{HCl} = 36,5\text{%}}$

`C_{M_{HCl}}= ?`

Giải:

`m_{\text{dd HCl}}=D × V=1,19 × 210= 249,9 (g)`

`=> m_{HCl}=(m_{dd} × \text{C%})/(100\text{%})=(249,9 × 36,5\text{%})/(100\text{%})= 91,2135 (g)`

`=> n_{HCl}=m/M=(91,2135)/(36,5)= 2,499 (mol)`

`=> C_{M_{HCl}}=n/V=(2,499)/(0,21)= 11,9 (M)`

$\text{Đáp án + giải thích các bước giải :}$

$Tóm$ $tắt$ $:$ 

$V_{\text{dung dịch HCl}}$ $=$ $210$ $(ml)$ 

$C\%_{\text{dung dịch HCl}}$ $=$ $36,5\%$ 

$D_{\text{dung dịch HCl}}$ $=$ $1,19$ $(g \ ml)$ 

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$C_{M_{\text{dung dịch HCl}}}$ $=$ $?$ $M$

$m_{\text{dung dịch HCl}}$ $=$ $210$ $×$ $1,19$ $=$ $249,9$ $(g)$ 

$⇒$ $m_{HCl}$ $=$ $249,9$ $×$ $36,5\%$ $=$ $91,2135$ $(g)$ 

$⇒$ $n_{HCl}$ $=$ $\frac{91,2135}{36,5}$ $=$ $2,499$ $(mol)$ 

$⇒$ $C_{M_{\text{dung dịch HCl}}}$ $=$ $\frac{2,499}{0,21}$ $=$ $11,9$ $M$

$\text{Chúc bn hk tốt !! :))))}$