a) Có: a//b (gt) nên:

⇒ $\widehat{A4}$ = $\widehat{B4}$ = $37^o$ (2 góc đồng vị)

b) Có: $\widehat{A1}$ + $\widehat{A4}$ = $180^o$ (Tính chất 2 góc kề bù)

          $\widehat{A1}$ + $37^o$ = $180^o$ (Thay số)

          $\widehat{A1}$ = $143^o$

    Có: $\widehat{A1}$ = $143^o$; $\widehat{B4}$ = $37^o$

⇒ $\widehat{A1}$ > $\widehat{B4}$

c) Có: $\widehat{B4}$ = $\widehat{B2}$ = $37^o$ (2 góc đối đỉnh)

Chúc bạn học tốt

$\\$

`a,`

$a//b$

`=>hat{A_4}=hat{B_4}=37^o` (2 góc đồng vị)

Vậy `hat{B_4}=37^o`

`b,`

`hat{A_4}+hat{A_1}=180^o` (2 góc kề bù)

`=>hat{A_1}=180^o-hat{A_4}=180^o-37^o=143^o`

Mà `hat{B_4}=37^o`

`=>hat{A_1} > hat{B_4}` (Do `143^o > 37^o`)

Vậy `hat{A_1}>hat{B_4}`

`c,`

$a//b$

`=>hat{A_4}=hat{B_2}=37^o` (2 góc so le trong)

Vậy `hat{B_2}=37^o`