A. \(25{{\lambda }_{2}}=36{{\lambda }_{1}}\)
B. \(6{{\lambda }_{2}}=5{{\lambda }_{1}}\)
C. \(256{{\lambda }_{2}}=675{{\lambda }_{1}}\)
D. \(675{{\lambda }_{2}}=256{{\lambda }_{1}}\)
C
Ta có:
\(\frac{hc}{{{\lambda }_{1}}}={{E}_{4}}-{{E}_{2}}=-\frac{13,6}{{{4}^{2}}}-\left( -\frac{13,6}{{{2}^{2}}} \right)=2,55\) (1)
\(\frac{hc}{{{\lambda }_{2}}}={{E}_{5}}-{{E}_{3}}=-\frac{13,6}{{{5}^{2}}}-\left( \frac{13,6}{{{3}^{2}}} \right)=\frac{1088}{1125}\) (2)
\(\frac{\left( 1 \right)}{\left( 2 \right)}=\frac{{{\lambda }_{2}}}{{{\lambda }_{1}}}=\frac{{{E}_{4}}-{{E}_{2}}}{{{E}_{5}}-{{E}_{3}}}=\frac{675}{246}\to 675{{\lambda }_{1}}=256{{\lambda }_{2}}\).
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