Thực hiện các phép tính sau:
a) \(\frac{3x-5}{7}+\frac{4x+5}{7}\);
b) \(\frac{5xy-4y}{2x^{2}y^{3}}+\frac{3xy+4y}{2x^{2}y^{3}}\)
c) \(\frac{x+1}{x-5}+\frac{x-18}{x-5}+\frac{x+2}{x-5}\).
Câu a:
\(\frac{3x-5}{7}+\frac{4x+5}{7}\) = \(\frac{3x-5+4x+5}{7}=\frac{7x}{7}=x\)
Câu b:
\(\frac{5xy-4y}{2x^{2}y^{3}}+\frac{3xy+4y}{2x^{2}y^{3}}\) = \(\frac{5xy-4y+3xy+4y}{2x^{2}y^{3}}=\frac{8xy}{2x^{2}y^{3}}=\frac{4}{xy^{2}}\)
Câu c:
\(\frac{x+1}{x-5}+\frac{x-18}{x-5}+\frac{x+2}{x-5}\)= \(\frac{x+1+x-18+x+2}{x-5}=\frac{3x-15}{x-5}=\frac{3(x-5)}{x-5}=3\)
-- Mod Toán 8
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