(A) sinα
(B) –sinα
(C) –cos α
(D) cosα
Ta có:
\(\sin ({{3\pi } \over 2} + \alpha ) = \sin (\pi + {\pi \over 2} + \alpha ) \)
\(= - \sin ({\pi \over 2}\, + \alpha ) = - \cos \alpha \)
Chọn (C)
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