Giải phương trinh (4x-5)^2-(7+2x)=4(2x-4)^2+6x

* Hướng dẫn giải

$\begin{array}{l}{\left(4x-5\right)}^2-\left(7+2x\right)=4{\left(2x-4\right)}^2+6x\\ \iff 16x^2-40x+25-7-2x=16x^2-32x+64+6x\\ \iff 16x=46\iff x=\frac{23}{8}S=\left\{\frac{23}{8}\right\}\end{array}$