Giải phương trình 1-(x/2+x/3)/1/2=(4x/3+x/4)/1/3+x

$1-\frac{\frac{x}{2}+\frac{x}{3}}{\frac{1}{2}}=\frac{\frac{4x}{3}+\frac{x}{4}}{\frac{1}{3}}+x\iff 1-2\left(\frac{3x}{6}+\frac{2x}{6}\right)=3\left(\frac{16x}{12}+\frac{3x}{12}\right)+x$

$\begin{array}{l}\iff 1-2\left(\frac{3x}{6}+\frac{2x}{6}\right)=3.\left(\frac{16x}{12}+\frac{3x}{12}\right)+x\\ \iff 1-\frac{5x}{3}=\frac{19x}{4}+x\iff \frac{89}{12}x=1\iff x=\frac{12}{89}\end{array}$