Giải phương trình (x+2)(3-4x)=x^2+4x+4

* Hướng dẫn giải

$\begin{array}{l}\left(x+2\right)\left(3-4x\right)=x^2+4x+4\iff \left(x+2\right)\left(3-4x\right)-{\left(x+2\right)}^2=0\\ \iff \left(x+2\right)\left(3-4x-x-2\right)=0\iff \left(x+2\right)\left(-5x+1\right)=0\iff \left[\begin{array}{l}x=-2\\ x=\frac{1}{5}\end{array}\right.\end{array}$