Giải phương trình (x-1)/(x+2)-x/(x+2)=-13/5

* Hướng dẫn giải

$\begin{array}{l}\frac{x-1}{x+2}-\frac{x}{x-2}=-\frac{13}{5}\left(x\ne \pm 2\right)\\ \iff \frac{\left(x-1\right)\left(x-2\right)-x\left(x+2\right)}{\left(x+2\right)\left(x-2\right)}=\frac{-13\left(x+2\right)\left(x-2\right)}{5\left(x+2\right)\left(x-2\right)}\\ \Rightarrow 5\left(x^2-3x+2\right)-5\left(x^2+2x\right)=-13\\ \iff -25x=-23\iff x=\frac{23}{25}\left(tm\right)\end{array}$