Giải phương trình (x-1)2-|5-3x|-x=x(x+2)+4

* Hướng dẫn giải

$\begin{array}{l}{\left(x+1\right)}^2-\left|5-3x\right|-x=x\left(x+2\right)+4\\ \iff x^2+2x+1-\left|5-3x\right|-x=x^2+2x+4\\ \iff \left|5-3x\right|=-3-x\\ +)x\ge \frac{5}{3}\Rightarrow 5-3x=-3-x\iff x=4(tm)\\ +)x<-\frac{5}{3}\Rightarrow 3x-5=-3-x\iff x=\frac{1}{2}(ktm)S=\left\{4\right\}\end{array}$