Giải phương trình x/(x-2)-5/(x+2)=(x^2+1)/(x^2-4)

* Hướng dẫn giải

$\begin{array}{l}\frac{x}{x-2}-\frac{5}{x+2}=\frac{x^2+1}{x^2-4}\left(x\ne \pm 2\right)\iff \frac{x\left(x+2\right)-5\left(x-2\right)}{\left(x-2\right)\left(x+2\right)}=\frac{x^2+1}{\left(x-2\right)\left(x+2\right)}\\ \Rightarrow -3x=-9\iff x=3\left(tm\right)\end{array}$