Tìm x: (x-1)^2 = 5x(x-1)

* Hướng dẫn giải

$\begin{array}{l}{\left(\mathrm{x}-1\right)}^2=5\mathrm{x}\left(\mathrm{x}-1\right)\\ \iff \left(\mathrm{x}-1\right)\left(\mathrm{x}-1-5\mathrm{x}\right)=0\\ \iff \left(\mathrm{x}-1\right)\left(-4\mathrm{x}-1\right)=0\Rightarrow \left[\begin{array}{l}\mathrm{x}=1\\ \mathrm{x}=-\frac{1}{4}\end{array}\right.\end{array}$