A. \(S=\left\{1 ; \frac{3}{4}\right\}\)
B. \(S=\left\{\frac{1}{2} ; \frac{3}{4}\right\}\)
C. \(S=\left\{\frac{1}{2} ; -1\right\}\)
D. \(S=\emptyset\)
B
Ta có
\(|3 x-2|=1-x \Leftrightarrow\left\{\begin{array}{l} 1-x \geq 0 \\ {\left[\begin{array}{l} 3 x-2=1-x \\ 3 x-2=-1+x \end{array}\right.} \end{array}\right.\)
\(\Leftrightarrow\left\{\begin{array}{l} x \leq 1 \\ {\left[\begin{array}{l} x=\frac{3}{4} \\ x=\frac{1}{2} \end{array}\right.} \end{array} \Leftrightarrow\left[\begin{array}{l} x=\frac{3}{4} \\ x=\frac{1}{2} \end{array}\right.\right.\)
Vậy \(S=\left\{\frac{1}{2} ; \frac{3}{4}\right\}\)
Câu hỏi trên thuộc đề trắc nghiệm dưới đây !
Copyright © 2021 HOCTAP247