Chọn câu đúng (4x^2 - 3x + 5)/(x^3 - 1) - (1 - 2x)/(x^2 + x + 1) - 6/(x - 1)

A. $\frac{4x^2-3x+5}{x^3-1}-\frac{1-2x}{x^2+x+1}-\frac{6}{x-1}=-\frac{12x}{x^3-1}$

B. $\frac{4x^2-3x+5}{x^3-1}-\frac{1-2x}{x^2+x+1}-\frac{6}{x-1}=\frac{12x}{x^3-1}$

C. $\frac{4x^2-3x+5}{x^3-1}-\frac{1-2x}{x^2+x+1}-\frac{6}{x-1}=-\frac{x}{x^3-1}$

D. $\frac{4x^2-3x+5}{x^3-1}-\frac{1-2x}{x^2+x+1}-\frac{6}{x-1}=-\frac{12x}{x-1}$