Tìm x biết: (x-3)^2-x+3=0

Cách giải:

${\left(x-3\right)}^2-x+3=0$

$\begin{array}{l}\iff {\left(x-3\right)}^2-\left(x-3\right)=0\\ \iff \left(x-3\right)\left(x-3-1\right)=0\\ \iff \left(x-3\right)\left(x-4\right)=0\\ \iff \left[\begin{array}{l}x-3=0\\ x-4=0\end{array}\right.\iff \left[\begin{array}{l}x=3\\ x=4\end{array}\right.\end{array}$