Giải phương trình 3/(x^2-3x)-(x+3)/(x-3)=-1/x

* Hướng dẫn giải

$\begin{array}{l}\frac{3}{x^2-3x}-\frac{x+3}{x-3}=\frac{-1}{x}\\ \iff \frac{3-x(x-3)}{x(x-3)}=\frac{-(x-3)}{x(x-3)}\left(\begin{array}{l}x\ne 0\\ x\ne 3\end{array}\right)\\ \Rightarrow 3-x^2+3x=-x+3\\ \iff x^2-4x=0\iff \left[\begin{array}{l}x=0\left(loai\right)\\ x=4(t/m)\end{array}\right.\\ S=\left\{4\right\}\end{array}$