Làm tính nhân: (2x – 1)(3x + 2)(3 – x)

* Hướng dẫn giải

$$\begin{gathered} \left(2x-1\right)\left(3x+2\right)\left(3-x\right) \\ =\left(6x^2+4x-3x-2\right)\left(3-x\right) \\ =\left(6x^2+x-2\right)\left(3-x\right) \\ =6x^2.\left(3-x\right)+x\left(3-x\right)-2\left(3-x\right) \\ =18x^2-6x^3+3x-x^2-6+2x \\ =17x^2-6x^3+5x-6 \end{gathered}$$