A. \(S=\left\{ \frac{9}{11}\right\}\)
B. \(S=\left\{1 ; 0\right\}\)
C. \(S=\left\{1 ; \frac{9}{11}\right\}\)
D. \(S=\left\{1 ; -\frac{9}{11}\right\}\)
C
Ta có
\(\begin{array}{l} {\rm{|4 - 5 x| = |5 - 6 x|}}\\ \Leftrightarrow \left[ \begin{array}{l} 4 - 5x = 5 - 6x\\ 4 - 5x = - \left( {5 - 6x} \right) \end{array} \right.\\ \Leftrightarrow \left[ \begin{array}{l} - 5x + 6x = 5 - 4\\ 4 - 5x = - 5 + 6x \end{array} \right.\\ \Leftrightarrow \left[ \begin{array}{l} - 5x + 6x = 5 - 4\\ - 5x - 6x = - 5 - 4 \end{array} \right.\\ \Leftrightarrow \left[ \begin{array}{l} x = 1\\ - 11x = - 9 \end{array} \right.\\ \Leftrightarrow \left[ \begin{array}{l} x = 1\\ x = \frac{9}{{11}} \end{array} \right.\\ \Rightarrow S = \left\{ {1;\frac{9}{{11}}} \right\} \end{array}\)
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