Chọn câu đúng (4^2x-3x+5)/(x^3-1)-(1-2x)/(x^2+x+1)-6/(x-1)

$A. \frac{4x^2-3x+5}{x^3-1}-\frac{1-2x}{x^2+x+1}-\frac{6}{x-1}=-\frac{12x}{x^3-1}$

$B. \frac{4x^2-3x+5}{x^3-1}-\frac{1-2x}{x^2+x+1}-\frac{6}{x-1}=\frac{12x}{x^3-1}$

$C. \frac{4x^2-3x+5}{x^3-1}-\frac{1-2x}{x^2+x+1}-\frac{6}{x-1}=-\frac{x}{x^3-1}$

$D. \frac{4x^2-3x+5}{x^3-1}-\frac{1-2x}{x^2+x+1}-\frac{6}{x-1}=-\frac{12x}{x-1}$