Trắc nghiệm Toán 8: Ôn tập chương 2 có đáp án (Nhận biết) !!

A. x ≠ 0

B. x ≠ - 2

C. x ≠ -2; x ≠ 0

D. x ≠ 3; x ≠ -2; x ≠ 0

$A. 3x(x - 2)$

$B. x - 2$

$C. 3x^2(x-2)$

$D. 3x{(x-2)}^2$

A. P = x + y

B. P = 5(x – y)

C. P = 5(y – x)

D. P = x

$A. \frac{-2x-1}{2xy}$

$B. \frac{-2x+1}{xy}$

$C. \frac{-2x+1}{2xy}$

$D. \frac{-2x-1}{xy}$

$A. \frac{4}{x^2{y}^2}$

$B. \frac{2}{2x{y}^2}$

$C. \frac{4}{5x^2{y}^2}$

$D. \frac{4}{x{y}^2}$

A. -x

B. 2x

C. $\frac{x}{2}$

D. x

$A. \frac{-x^2+15}{2(x+3)}$

$B. \frac{x^2-15}{2(x+3)}$

$C. \frac{-x^2-15}{2(x+3)}$

D. Cả A, B, C đều sai

$A. \frac{x+20}{x(x+10)}$

$B. \frac{x+9}{x+10}$

$C. \frac{1}{x+10}$

$D. \frac{1}{x(x+1)(x+10)}$

$A. \frac{x+2}{x + 1}$

$B. \frac{2}{x + 1}$

$C. \frac{2}{2x + 1}$

$D. \frac{1}{2x + 1}$

$A. \frac{4x^2-3x+5}{x^3-1}-\frac{1-2x}{x^2+x+1}-\frac{6}{x-1}=-\frac{12x}{x^3-1}$

$B. \frac{4x^2-3x+5}{x^3-1}-\frac{1-2x}{x^2+x+1}-\frac{6}{x-1}=\frac{12x}{x^3-1}$

$C. \frac{4x^2-3x+5}{x^3-1}-\frac{1-2x}{x^2+x+1}-\frac{6}{x-1}=-\frac{x}{x^3-1}$

$D. \frac{4x^2-3x+5}{x^3-1}-\frac{1-2x}{x^2+x+1}-\frac{6}{x-1}=-\frac{12x}{x-1}$

$A. P=\frac{x}{x+3}$

$B. P=\frac{x}{x-3}$

$C. P=\frac{2x}{x-3}$

$D. P=\frac{x-3}{x}$

$A. \frac{3(x-2)}{x+2}$

$B. \frac{3(x+5)}{x-2}$

$C. \frac{3}{x-2}$

$D. \frac{3}{x+2}$

$A. \frac{2x}{5(x^2+4)}$

$B. \frac{6x}{5(x^2+4)}$

$C. \frac{3x}{5(x^2+4)}$

$D. \frac{x}{5(x^2+4)}$

$A. \frac{1}{2-x}$

$B. \frac{x+2}{x-2}$

$C. \frac{x+2}{2-x}$

$D. \frac{1}{x-2}$

$A. \frac{x+1}{x-1}$

$B. \frac{x-1}{x+1}$

$C. \frac{x-1}{5(x+1)}$

$D. \frac{x+1}{5(x-1)}$

A. x = -6

B. x = -5

C. x = -7

D. Không có x thoả mãn

$A. \frac{3}{x-6}$

$B. x+6$

$C. \frac{x+6}{3}$

$D. \frac{3}{x+6}$

A. M = -5x(x-2y)

B. M = 5x(x-2y)

C. M = x(x-2y)

D. M = 5x(x+2y)

$A. \frac{1-3x}{x-1}$

$B. \frac{3x-1}{x-1}$

$A. \frac{-3x-1}{x-1}$

$D. \frac{1-3x}{-x-1}$

$A. \frac{(x-1)(x-2)}{2}$

$B. \frac{1}{(x-1)(x-2)}$

$C. \frac{-2}{(x-1)(x-2)}$

$D. \frac{2}{(x-1)(x-2)}$

$A. Q=\frac{1}{x^2+9}$

$B. Q=\frac{x-3}{x+3}$

$C. Q=\frac{1}{x-3}$

$D. Q=\frac{x+3}{x-3}$

$A. P=\frac{7-3x}{x+4}$

$B. P=\frac{-7-3x}{x+4}$

$C. P=\frac{-3x+7}{x+4}$

$D. P=\frac{7+3x}{x+4}$

$A. P=\frac{7}{4}$

$B. P=\frac{4}{3}$

$C. P=\frac{10}{3}$

$D. P=\frac{-10}{3}$

$A. x\in \left\{-23, -5, -3\right\}$

$B. x\in \left\{-23, -5, -3, 15\right\}$

$C. x\in \left\{-5, -3, 15\right\}$

$D. x\in \left\{-1, -19, 1, 19\right\}$

A. A < -2

B. 0 < A < 1

C. A  > 0

D. A < -1

A. 5

B. -5

C. 2

D. -2