Chọn khẳng định đúng (1/(x^2+4x+4-1/(x^2-4x+4):(1/(x+2)+1/(x-2)

$A. \left(\frac{1}{x^2+4x+4}-\frac{1}{x^2-4x+4}\right):\left(\frac{1}{x+2}+\frac{1}{x-2}\right)=\frac{-4}{x^2-4}$

$B. \left(\frac{1}{x^2+4x+4}-\frac{1}{x^2-4x+4}\right):\left(\frac{1}{x+2}+\frac{1}{x-2}\right)=\frac{4}{x^2-4}$

$C. \left(\frac{1}{x^2+4x+4}-\frac{1}{x^2-4x+4}\right):\left(\frac{1}{x+2}+\frac{1}{x-2}\right)=\frac{8}{x^2-4}$

$D. \left(\frac{1}{x^2+4x+4}-\frac{1}{x^2-4x+4}\right):\left(\frac{1}{x+2}+\frac{1}{x-2}\right)=\frac{-8}{x^2-4}$