Thủy phân saccarozơ trong môi trường axit thu được

Thủy phân saccarozơ trong môi trường axit thu được: Glucozơ và fructozơ

Phương trình phản ứng: $\begin{array}{l}{C}_{12}{H}_{22}{O}_{11}+H_{2}O\stackrel{H^{+},t°}{\to }{C}_6{H}_{12}{O}_6+C_6{H}_{12}{O}_6\\ \text{ \hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em} (glucozo) (fructozo)}\end{array}\begin{array}{l}{C}_{12}{H}_{22}{O}_{11}+H_{2}O\stackrel{H^{+},t°}{\to }{C}_6{H}_{12}{O}_6+C_6{H}_{12}{O}_6\\ \text{ \hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em} (glucozo) (fructozo)}\end{array}$

Chọn đáp án A.