Thực hiện dãy chuyển hóa sau: Al-->Al2O3--->AlCl3--->Al(OH)3--->Na[Al(OH)4]

* Hướng dẫn giải

$\left(1\right)2Al+3O_2\stackrel{t^o}{\to }2A{l}_2{O}_3$

$\left(2\right)A{l}_2{O}_3+6HCl\to 2AlC{l}_3+3H_{2}O$

$\left(3\right)AlC{l}_3+3NaOH\to 3NaCl+Al{\left(OH\right)}_3\downarrow$

$\left(4\right)Al{\left(OH\right)}_3+NaOH\to Na\left[Al{\left(OH\right)}_4\right]$