Giải phương trình chứa ẩn ở mẫu sau : x + 2/x - 1 = 4x^2 - 11x - 2/(1 - x)(x + 2)

* Hướng dẫn giải

$\begin{array}{l}\frac{x+2}{x-1}=\frac{4x^2-11x-2}{\left(1-x\right)\left(x+2\right)}\left(\begin{array}{l}x\ne 1\\ x\ne -2\end{array}\right)\\ \iff \frac{{\left(x+2\right)}^2}{\left(x+2\right)\left(x-1\right)}=\frac{11x+2-4x^2}{\left(x+2\right)\left(x-1\right)}\\ \Rightarrow x^2+4x+4=11x+2-4x^2\iff 5x^2-7x+2=0\iff \left[\begin{array}{l}x=1\left(ktm\right)\\ x=\frac{2}{5}\left(tm\right)\end{array}\right.\end{array}$