Giải phương trình : 2/x^2 - 4 - 1/x(x - 2) + x - 4/x(x + 2) = 0

* Hướng dẫn giải

$\begin{array}{l}\frac{2}{x^2-4}-\frac{1}{x\left(x-2\right)}+\frac{x-4}{x\left(x+2\right)}=0\left(\begin{array}{l}x\ne 0\\ x\ne \pm 2\end{array}\right)\\ \Rightarrow 2x-\left(x+2\right)+\left(x-4\right)\left(x-2\right)=0\\ \iff x^2-5x+6=0\iff \left[\begin{array}{l}x=2\left(ktm\right)\\ x=3\left(tm\right)\end{array}\right.\end{array}$