Giải phương trình 2/x^2 - 4 - 1/ x(x - 2) + x - 4/x(x + 2) = 0

* Hướng dẫn giải

$\frac{2}{x^2-4}-\frac{1}{x\left(x-2\right)}+\frac{x-4}{x\left(x+2\right)}=0\left(\begin{array}{l}x\ne 0\\ x\ne \pm 2\end{array}\right)$

$\begin{array}{l}\Rightarrow 2x-\left(x+2\right)+\left(x-2\right)\left(x-4\right)=0\\ \iff \left(x-2\right)\left(-x-3\right)=0\iff \left[\begin{array}{l}x=2\\ x=-3\end{array}\right.\end{array}$