A. \(\frac{8}{3}-\sqrt{3}\)
B. \(\frac{8}{3}+\sqrt{3}\)
C. \(\frac{8}{3}-\sqrt{2}\)
D. \(\frac{8}{3}+\sqrt{2`}\)
B
Ta có
\(\begin{array}{l} \mathrm{C}=2 \sqrt{3}+\sqrt{7-4 \sqrt{3}}+\left(\sqrt{\frac{1}{3}}-\sqrt{\frac{4}{3}}+\sqrt{3}\right): \sqrt{3} \\ =2 \sqrt{3}+\sqrt{(2-\sqrt{3})^{2}}+\left(\frac{1}{3} \sqrt{3}-\frac{2}{3} \sqrt{3}+\sqrt{3}\right) \cdot \frac{1}{\sqrt{3}} \\ =2 \sqrt{3}+|2-\sqrt{3}|+\frac{2}{3} \sqrt{3} \frac{1}{\sqrt{3}} \\ =2 \sqrt{3}+(2-\sqrt{3})+\frac{2}{3} \sqrt{3} \frac{1}{\sqrt{3}} \\ =\frac{8}{3}+\sqrt{3} \end{array}\)
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