Cho sơ đồ phản ứng theo đúng tỉ lệ mol:(a) \(X+2NaOH\to {{X}_{1}}+2{{X}_{2}}\)(b) \({{X}_{1}}+{{H}_{2}}S{{O}_{4}}\to {{X}_{3}}+

* Hướng dẫn giải

Đáp án D

\(\left( c \right)\,\,\,np{\rm{ - HCOOC - }}{{\rm{C}}_6}{{\rm{H}}_4}{\rm{ - C}}OONa\left( {{X_3}} \right) + {\rm{n}}{{\rm{C}}_2}{H_4}{\left( {OH} \right)_2}\left( {{X_4}} \right) \to poli\left( {etilen{\rm{ - terephtalat}}} \right) + 2n{H_2}O.\)

\(\left( b \right)\,\,{\rm{ p - NaOOC - }}{{\rm{C}}_6}{{\rm{H}}_4}{\rm{ - C}}OONa\left( {{X_1}} \right) + {H_2}S{O_4} \to {\rm{ p - HOOC - }}{{\rm{C}}_6}{{\rm{H}}_4}{\rm{ - C}}OOH\left( {{X_3}} \right) + N{a_2}S{O_4}.\)

\(\left( d \right)\,\,\,C{H_3}OH\left( {{X_2}} \right) + CO \to C{H_3}COOH\left( {{X_5}} \right).\)

\(\left( a \right)\,\,\,{\rm{p - C}}{{\rm{H}}_3}{\rm{ - OOC - }}{{\rm{C}}_6}{{\rm{H}}_4}{\rm{ - C}}OO{\rm{ - C}}{{\rm{H}}_3}\left( X \right) + 2NaOH \to {\rm{p - NaOOC - }}{{\rm{C}}_6}{{\rm{H}}_4}{\rm{ - C}}OONa + 2C{H_3}OH\left( {{X_2}} \right).\)

\(\left( e \right)\,\,{C_2}{H_4}{\left( {OH} \right)_2} + 2C{H_3}COOH \mathbin{\lower.3ex\hbox{$\buildrel\textstyle\rightarrow\over
{\smash{\leftarrow}\vphantom{_{\vbox to.5ex{\vss}}}}$}} {\left( {C{H_3}COO} \right)_2}{C_2}{H_4}\left( {{X_6}} \right) + 2{H_2}O.\)