A. 24,58.
B. 25,14.
C. 22,08.
D. 20,16.
C
Đáp án C.
\(\text{X}\left\{ \begin{array}{*{35}{l}} {{\text{C}}_{n}}{{\text{H}}_{2n}}{{\text{O}}_{2}}:0,2\left( {{n}_{\text{KOH }}} \right) \\ {{\text{C}}_{m}}{{\text{H}}_{2m+3}}~\text{N}:x \\ {{\text{C}}_{m}}{{\text{H}}_{2m+4}}~{{\text{N}}_{2}}:x \\ \end{array}\quad \to x+2x=2{{n}_{{{\text{N}}_{2}}}}=0,24\to x=0,08 \right.\)
\(n_{\mathrm{O}_{2}}=1,2 \rightarrow 0,2 .(1,5 n-1)+0,08 .(1,5 m+0,75)+0,08 .(1,5 t+1)=1,2\)
\(\rightarrow 15 n+6 m+6 t=63 \rightarrow\left\{\begin{array}{l} n=3 \\ m=1 \\ t=2 \end{array} \rightarrow \mathrm{X}\left\{\begin{array}{l} \mathrm{C}_{3} \mathrm{H}_{6} \mathrm{O}_{2}: 0,2 \\ \mathrm{CH}_{5} \mathrm{~N}: 0,08 \\ \mathrm{C}_{2} \mathrm{H}_{8} \mathrm{~N}_{2}: 0,08 \end{array}\right.\right.\)
\(\to m=22,08\,\,(~\text{g})\)
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