Tìm x, biết:
(12x−5)(4x−1) + (3x−7)(1−16x) = 81.
(12x−5)(4x−1) + (3x−7)(1−16x) = 81
\(\Leftrightarrow 48x^2-12x-20x+5+3x-48x^2-7+112x=81\)
\(\Leftrightarrow 83x-2=81\Leftrightarrow 83x=83 \Leftrightarrow x=1\)
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