A. 5
B. 4
C. 3
D. 6
A
Đáp án A
\(\begin{align} & \left( a \right)AlC{{l}_{3}}+3N{{H}_{3}}+3{{H}_{2}}O\to Al{{\left( OH \right)}_{3}}\downarrow +3N{{H}_{4}}Cl \\ & \left( b \right)2KMn{{O}_{4}}+3C{{H}_{2}}=C{{H}_{2}}+4{{H}_{2}}O\to 3HOC{{H}_{2}}-C{{H}_{2}}OH+2Mn{{O}_{2}}\downarrow +2KOH \\ & \left( c \right)2NaOH+Ca{{\left( HC{{O}_{3}} \right)}_{2}}\to CaC{{O}_{3}}\downarrow +N{{a}_{2}}C{{O}_{3}}+2{{H}_{2}}O \\ & \left( d \right)2C{{O}_{2}}+Ba{{\left( OH \right)}_{2}}\to Ba{{\left( HC{{O}_{3}} \right)}_{2}} \\ & \left( e \right)S{{O}_{2}}+2{{H}_{2}}S\to 3S\downarrow +2{{H}_{2}}O \\ & \left( f \right)2K+2{{H}_{2}}O\to 2KOH+{{H}_{2}} \\ & \ \ \ \ 4KOH+ZnC{{l}_{2}}\to 2{{K}_{2}}\text{ }\!\!(\!\!\text{ }Zn{{(OH)}_{4}}\text{ }\!\!)\!\!\text{ }+2KCl \\ & \left( g \right)2{{H}_{3}}P{{O}_{4}}+3Ca{{\left( OH \right)}_{2}}\to C{{a}_{3}}{{\left( P{{O}_{4}} \right)}_{2}}\downarrow +6{{H}_{2}}O \\ \end{align}\)
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