Cho các sơ đồ phản ứng: Glyxin (→(+NaOH) ) X →+HCl dư) ) Y (1) Glyxin (→(+HCl) ) Z (→(+NaOH dư) ) T

* Hướng dẫn giải

*Sơ đồ (1): $H_{2}NC{H}_{2}COOH \stackrel{+NaOH}{\to }{H}_{2}NC{H}_{2}COONa\left(X\right) \stackrel{+NaOH}{\to }Cl{H}_{3}NC{H}_{2}COOH\left(Y\right)$

PTHH:

$$\begin{gathered} H_{2}NC{H}_{2}COOH+NaOH\to H_{2}NC{H}_{2}COONa+H_{2}O \\ {H}_{2}NC{H}_{2}COONa+HCl\to Cl{H}_{3}NC{H}_{2}COOH +NaCl \end{gathered}$$
*Sơ đồ (2): $H_{2}NC{H}_{2}COOH \stackrel{+HCl}{\to }Cl{H}_{3}NC{H}_{2}COOH\left(Z\right)\stackrel{+NaOH dd}{\to } H_{2}NC{H}_{2}COONa\left(T\right)$

PTHH:

$\begin{array}{l}{H}_{2}NC{H}_{2}COOH+HCl\to Cl{H}_{3}NC{H}_{2}COOH \\ Cl{H}_{3}NC{H}_{2}COOH+NaOH\to H_{2}NC{H}_{2}COONa +H_{2}O+NaCl\end{array}$

Đáp án cần chọn là: C