Cho hàm x \right) = {\left( {2x + 1} Tính 0

* Hướng dẫn giải

Ta có

\(\begin{array}{l}f'\left( x \right) = 12{\left( {2x + 1} \right)^{11}}\left( {2x + 1} \right)'\\ = 24{\left( {2x + 1} \right)^{11}}\\f''\left( x \right) = 24.11{\left( {2x + 1} \right)^{10}}.\left( {2x + 1} \right)'\\ = 528{\left( {2x + 1} \right)^{10}}\\ \Rightarrow f''\left( 0 \right) = {528.1^{10}} = 528\end{array}\)