Cho \(\mathop {\lim }\limits_{x \to 1} \frac{{f(x) + 1}}{{x - 1}} =  - 1\).

Câu hỏi :

Cho \(\mathop {\lim }\limits_{x \to 1} \frac{{f(x) + 1}}{{x - 1}} =  - 1\). Tính \(\mathop {I = \lim }\limits_{x \to 1} \frac{{\left( {{x^2} + x} \right)f\left( x \right) + 2}}{{x - 1}}\)