Tính \(\mathop {\lim }\limits_{x \to  - {3^ - }} f\left( x \right) = \mathop {\lim }\limits_{x \to  - {3^ - }} \frac{{2x + 7}}{{x + 3}}.\)

Câu hỏi :

Tính \(\mathop {\lim }\limits_{x \to  - {3^ - }} f\left( x \right) = \mathop {\lim }\limits_{x \to  - {3^ - }} \frac{{2x + 7}}{{x + 3}}.\)

A. \(\mathop {\lim }\limits_{x \to  - {3^ - }} f\left( x \right) =  - \infty .\)

B. \(\mathop {\lim }\limits_{x \to  - {3^ - }} f\left( x \right) = \frac{7}{3}.\)

C. \(\mathop {\lim }\limits_{x \to  - {3^ - }} f\left( x \right) = 2.\)

D. \(\mathop {\lim }\limits_{x \to  - {3^ - }} f\left( x \right) =  + \infty .\)

* Đáp án

A

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