Nghiệm của phương trình \(\sin \left( {4x + \frac{1}{2}} \right) = \frac{1}{3}\) là:

A. \(\left[ \begin{array}{l}
x =  - \frac{1}{8} + k\frac{\pi }{2}\\
x = \frac{\pi }{4} + k\frac{\pi }{2}
\end{array} \right.,k \in Z\)

B. \(\left[ \begin{array}{l}
x =  - \frac{1}{8} - \frac{1}{4}\arcsin \frac{1}{3} + k\frac{\pi }{2}\\
x = \frac{\pi }{4} - \frac{1}{8} - \frac{1}{4}\arcsin \frac{1}{3} + k\frac{\pi }{2}
\end{array} \right.,k \in Z\)

C. \(\left[ \begin{array}{l}
x = \frac{1}{8} - \frac{1}{4}\arcsin \frac{1}{3} + k\frac{\pi }{2}\\
x = \frac{\pi }{4} - \frac{1}{8} - \frac{1}{4}\arcsin \frac{1}{3} + k\frac{\pi }{2}
\end{array} \right.,k \in Z\)

D. \(\left[ \begin{array}{l}
x =  - \frac{1}{8} - \frac{1}{4}\arcsin \frac{1}{3} + k\frac{\pi }{2}\\
x = \frac{\pi }{4} - \frac{1}{4}\arcsin \frac{1}{3} + k\frac{\pi }{2}
\end{array} \right.,k \in Z\)