Tính \(\lim \dfrac{{{{2018}^n} + {2^{2018}}}}{{{{2019}^n}}}\).

* Hướng dẫn giải

Ta có:

\(\begin{array}{l}\,\,\,\,\lim \dfrac{{{{2018}^n} + {2^{2018}}}}{{{{2019}^n}}}\\ = \lim \left[ {{{\left( {\dfrac{{2018}}{{2019}}} \right)}^n} + \dfrac{{{2^{2018}}}}{{{{2019}^n}}}} \right]\\ = 0 + 0 = 0\end{array}\)

Chọn A.