Cho khai triển P(x)=(1+x)(1+2x)...(1+2017x)=a0+a1x+...+a2017x^2017

Câu hỏi :

Cho khai triển $$\begin{gathered} P\left(x\right)=\left(1+x\right)\left(1+2x\right)...\left(1+2017x\right) \\ =a_0+a_{1}x+...+a_{2017}{x}^{2017} \end{gathered}$$.