\(\mathop {\lim }\limits_{x \to {3^ + }} \frac{{x + 1}}{{2x - 6}}\) là: 

Câu hỏi :

\(\mathop {\lim }\limits_{x \to {3^ + }} \frac{{x + 1}}{{2x - 6}}\) là: 

A. \(\frac{1}{2}\)

B. \(\frac{1}{6}\)

C. \( - \infty \)

D. \( + \infty \)

* Đáp án

D

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