lim (2x + 1)/(x - 2) x tiến đến 2 bằng

$\left.\begin{array}{l}\underset{\mathrm{x}\to 2^{+}}{\lim }\left(2\mathrm{x}+1\right)=5\\ \underset{\mathrm{x}\to 2^{+}}{\lim }\left(\mathrm{x}-2\right)=0\\ \mathrm{x}-2>0,\forall \mathrm{x}>2\end{array}\right\}\Rightarrow \underset{\mathrm{x}\to 2^{+}}{\lim }\frac{2\mathrm{x}+1}{\mathrm{x}-2}=+\infty .$ 

Vậy chọn phương án A.