lim (x^2 - 4)/(x^2 - 3x + 2) x tiến đến 2 bằng

$$\begin{gathered} \underset{\mathrm{x}\to 2}{\lim }\left(\frac{{\mathrm{x}}^2-4}{{\mathrm{x}}^2-3\mathrm{x}+2}\right)=\underset{\mathrm{x}\to 2}{\lim }\frac{\left(\mathrm{x}-2\right)\left(\mathrm{x}+2\right)}{\left(\mathrm{x}-2\right)\left(\mathrm{x}-1\right)} \\ =\underset{\mathrm{x}\to 2}{\lim }\frac{\mathrm{x}+2}{\mathrm{x}-1}=\frac{2+2}{2-1}=4. \end{gathered}$$

Vậy chọn phương án C.