lim x tiến đến 2+ (2x+3)/(2−x) bằng

Ta có: $\left\{\begin{array}{l}\underset{\mathrm{x}\to 2^{+}}{\lim }\left(2\mathrm{x}+3\right)=7>0\\ \underset{\mathrm{x}\to 2^{+}}{\lim }\left(2-\mathrm{x}\right)=0\\ 2-\mathrm{x}<0\mathrm{khi}\mathrm{x}\to 2^{+}\end{array}\right.$

Vậy: $\underset{\mathrm{x}\to 2^{+}}{\lim }\frac{2\mathrm{x}+3}{2-\mathrm{x}}=-\infty$

Chọn đáp án D.